Question 0 of 18

Drug Classification  ·  Questions 1–6

Identify the pharmacological class or categorical label for each drug or receptor. Vocabulary preparation is sufficient to answer every question in this section.

Question 1

Which of the following correctly classifies cyclophosphamide within the alkylating agent subgroups?

  • ANitrogen mustard
  • BPlatinum compound
  • CNitrosourea
  • DAlkyl sulfonate

Correct Answer

A — Nitrogen mustard

Rationale

Cyclophosphamide is classified as a nitrogen mustard alkylating agent. Nitrogen mustards generate aziridinium ion intermediates that alkylate deoxyribonucleic acid and include cyclophosphamide, ifosfamide, mechlorethamine, melphalan, chlorambucil, and bendamustine. Platinum compounds (cisplatin, carboplatin, oxaliplatin) form platinum-deoxyribonucleic acid adducts after aquation. Nitrosoureas (carmustine, lomustine) are highly lipophilic agents with central nervous system penetration. Alkyl sulfonates (busulfan) have selectivity for hematopoietic stem cells.

Question 2

Which of the following correctly classifies cisplatin within the alkylating agent subgroups?

  • ANitrogen mustard
  • BNitrosourea
  • CPlatinum compound
  • DTriazene

Correct Answer

C — Platinum compound

Rationale

Cisplatin is classified as a platinum compound. Platinum compounds form covalent platinum-deoxyribonucleic acid adducts after aquation and include cisplatin, carboplatin, and oxaliplatin. Nitrogen mustards (cyclophosphamide, ifosfamide) generate aziridinium ion intermediates. Nitrosoureas (carmustine, lomustine) are lipophilic agents used for central nervous system tumors. Triazenes (temozolomide, dacarbazine) generate methylating species after metabolic or spontaneous activation.

Question 3

Which of the following correctly classifies temozolomide within the alkylating agent subgroups?

  • ANitrogen mustard
  • BTriazene
  • CNitrosourea
  • DPlatinum compound

Correct Answer

B — Triazene

Rationale

Temozolomide is classified as a triazene (specifically an imidazotetrazine) that generates a methylating species through spontaneous hydrolysis at physiological pH. The triazene and hydrazine subgroup, which also includes dacarbazine and procarbazine, requires metabolic or spontaneous activation to produce methylating intermediates. Nitrogen mustards generate aziridinium ions. Nitrosoureas (carmustine, lomustine) are lipophilic central nervous system-penetrating alkylating agents. Platinum compounds form platinum-deoxyribonucleic acid adducts after aquation.

Question 4

Which of the following correctly classifies carmustine within the alkylating agent subgroups?

  • AAlkyl sulfonate
  • BPlatinum compound
  • CNitrogen mustard
  • DNitrosourea

Correct Answer

D — Nitrosourea

Rationale

Carmustine is classified as a nitrosourea. Nitrosoureas, which also include lomustine and streptozocin, are distinguished by their high lipophilicity enabling passive diffusion across the blood-brain barrier, and by their characteristically delayed and prolonged myelosuppression nadir at 4 to 6 weeks. Alkyl sulfonates (busulfan) have selectivity for hematopoietic stem cells. Platinum compounds (cisplatin, carboplatin, oxaliplatin) form platinum-deoxyribonucleic acid adducts. Nitrogen mustards (cyclophosphamide, ifosfamide) generate aziridinium intermediates.

Question 5

Which of the following correctly classifies busulfan within the alkylating agent subgroups?

  • AAlkyl sulfonate
  • BNitrosourea
  • CNitrogen mustard
  • DTriazene

Correct Answer

A — Alkyl sulfonate

Rationale

Busulfan is classified as an alkyl sulfonate. The alkyl sulfonates have particular selectivity for hematopoietic stem cells, which is the basis for busulfan's primary clinical use as a myeloablative conditioning agent before hematopoietic stem cell transplantation. Nitrosoureas (carmustine, lomustine) penetrate the central nervous system and produce delayed myelosuppression. Nitrogen mustards (cyclophosphamide, ifosfamide, melphalan) generate aziridinium intermediates. Triazenes (temozolomide, dacarbazine) generate methylating species.

Question 6

Which of the following correctly classifies mesna?

  • AAlkylating agent
  • BGranulocyte colony-stimulating factor
  • CUroprotective thiol agent
  • DNeurokinin-1 receptor antagonist

Correct Answer

C — Uroprotective thiol agent

Rationale

Mesna (sodium 2-mercaptoethane sulfonate) is classified as a uroprotective thiol agent. It is administered alongside ifosfamide and high-dose cyclophosphamide to prevent hemorrhagic cystitis. Mesna itself has no antitumor activity and is not an alkylating agent, a colony-stimulating factor, or an antiemetic. Granulocyte colony-stimulating factors (filgrastim, pegfilgrastim) prevent febrile neutropenia. Neurokinin-1 receptor antagonists (aprepitant) prevent delayed-phase chemotherapy-induced nausea.

Core Pharmacology  ·  Questions 7–14

Apply your understanding of drug mechanisms, pharmacokinetics, and adverse effects. Each question requires one reasoning step.

Question 7

Cyclophosphamide is an inactive prodrug. Which of the following correctly describes the metabolic pathway that generates both its active alkylating species and the metabolite responsible for hemorrhagic cystitis?

  • ARenal tubular secretion converts cyclophosphamide to phosphoramide mustard, with acrolein excreted as a byproduct of glomerular filtration
  • BHepatic cytochrome P450 2B6 oxidizes cyclophosphamide to 4-hydroxycyclophosphamide, which decomposes to yield phosphoramide mustard as the active alkylating species and acrolein as the toxic urinary byproduct
  • CIntracellular glutathione transferases convert cyclophosphamide directly to phosphoramide mustard; acrolein is generated only when the dose exceeds the renal elimination threshold
  • DIntestinal esterases hydrolyze cyclophosphamide to acrolein, and hepatic aldehyde oxidase further converts acrolein to phosphoramide mustard

Correct Answer

B — Hepatic cytochrome P450 2B6 oxidizes cyclophosphamide to 4-hydroxycyclophosphamide, which decomposes to yield phosphoramide mustard as the active alkylating species and acrolein as the toxic urinary byproduct

Rationale

Cyclophosphamide is an inactive prodrug requiring hepatic oxidation, principally by cytochrome P450 2B6, to generate 4-hydroxycyclophosphamide. This intermediate spontaneously decomposes in tissues to yield two products: phosphoramide mustard, the bifunctional alkylating species responsible for antitumor activity, and acrolein, a reactive aldehyde excreted unchanged in urine that accumulates in the bladder lumen and causes direct urothelial cytotoxicity. The site of activation is hepatic, not renal or intestinal, and acrolein is generated as an obligate byproduct of the same decomposition step that produces the active drug.

Question 8

A patient is scheduled to receive ifosfamide for soft tissue sarcoma. Mesna is prescribed alongside the ifosfamide to prevent hemorrhagic cystitis. Which of the following best explains the mechanism by which mesna provides uroprotection?

  • AMesna alkalinizes the urine, reducing the concentration of acrolein in the bladder by promoting its ionization and decreasing its membrane permeability
  • BMesna competitively inhibits cytochrome P450 2B6, reducing the rate of ifosfamide activation and thereby limiting acrolein production
  • CMesna stimulates urothelial prostaglandin synthesis, which protects the bladder mucosa from acrolein-induced oxidative injury
  • DMesna contains a free thiol group that reacts with acrolein in the urinary tract to form a stable, non-toxic conjugate that is excreted renally

Correct Answer

D — Mesna contains a free thiol group that reacts with acrolein in the urinary tract to form a stable, non-toxic conjugate that is excreted renally

Rationale

Mesna (sodium 2-mercaptoethane sulfonate) exerts its uroprotective effect through a direct chemical reaction in the urinary tract. Its free thiol group undergoes nucleophilic addition to acrolein, forming a stable and non-toxic thioether conjugate that is excreted in the urine without causing urothelial injury. This reaction occurs in the bladder lumen after mesna is filtered and excreted, not systemically. Mesna does not alkalinize urine, does not inhibit cytochrome P450 2B6, and has no prostaglandin-related mechanism; it is purely a chemical scavenger of the toxic acrolein byproduct.

Question 9

A patient with bladder cancer is to receive cisplatin. Which of the following best explains why aggressive intravenous hydration with normal saline and supplemental magnesium are required with every cisplatin cycle?

  • ACisplatin causes dose-dependent tubular injury; saline diuresis dilutes urinary cisplatin concentrations and reduces tubular exposure, while magnesium replacement corrects the renal magnesium wasting that results from tubular damage
  • BCisplatin precipitates in acidic urine; saline increases urinary pH to prevent precipitation, and magnesium stabilizes the cisplatin molecule during renal excretion
  • CSaline competes with cisplatin for plasma protein binding, increasing the free fraction available for renal excretion, while magnesium prevents cisplatin-induced ototoxicity
  • DCisplatin activates the renin-angiotensin-aldosterone system; saline suppresses renin release and magnesium blocks aldosterone-mediated sodium retention

Correct Answer

A — Cisplatin causes dose-dependent tubular injury; saline diuresis dilutes urinary cisplatin concentrations and reduces tubular exposure, while magnesium replacement corrects the renal magnesium wasting that results from tubular damage

Rationale

Cisplatin nephrotoxicity is dose-dependent and cumulative, caused by direct tubular injury that reduces glomerular filtration rate and impairs tubular transport functions. Pre-hydration with at least 1 to 2 liters of normal saline before cisplatin administration dilutes urinary cisplatin concentrations, promotes diuresis, and reduces the duration of tubular exposure to the drug. Renal tubular injury specifically impairs magnesium reabsorption in the thick ascending limb, producing obligatory urinary magnesium wasting that persists between cycles; supplemental magnesium must therefore be given with every cycle regardless of serum levels. Cisplatin does not precipitate in acidic urine, does not displace protein binding through saline competition, and does not activate the renin-angiotensin-aldosterone system as its primary toxicity mechanism.

Question 10

A patient with ovarian cancer is to receive carboplatin. The oncologist uses the Calvert formula rather than body surface area to calculate the dose. Which of the following best explains the pharmacokinetic rationale for this approach?

  • ACarboplatin undergoes extensive hepatic first-pass metabolism, and the Calvert formula corrects for individual variation in cytochrome P450 activity
  • BCarboplatin binds plasma proteins in proportion to serum albumin, and the Calvert formula uses albumin concentration to predict free drug exposure
  • CCarboplatin is eliminated almost exclusively by renal filtration, so glomerular filtration rate is the primary determinant of drug exposure; the Calvert formula uses target area under the curve multiplied by the sum of glomerular filtration rate and 25 to achieve predictable dosing
  • DCarboplatin is distributed into a volume that correlates with body weight rather than surface area, and the Calvert formula converts surface area-based dosing to weight-based dosing

Correct Answer

C — Carboplatin is eliminated almost exclusively by renal filtration, so glomerular filtration rate is the primary determinant of drug exposure; the Calvert formula uses target area under the curve multiplied by the sum of glomerular filtration rate and 25 to achieve predictable dosing

Rationale

Carboplatin is eliminated almost entirely by renal glomerular filtration. Because individual variation in renal function determines how quickly the drug is cleared, a fixed body surface area-based dose produces widely varying drug exposures — underdosing patients with high glomerular filtration rates and overdosing those with impaired renal function. The Calvert formula directly addresses this by using target area under the curve as the dosing objective: dose (mg) = target area under the curve × (glomerular filtration rate + 25). The constant 25 accounts for non-renal clearance. This approach ties the dose to individual renal function and achieves predictable thrombocytopenic toxicity and antitumor exposure regardless of body habitus or renal status variation. Carboplatin does not undergo significant hepatic metabolism and its protein binding does not determine dose.

Question 11

A patient with anaplastic glioma receives lomustine as part of the PCV regimen. The oncologist schedules the next cycle no sooner than 6 weeks after the first. Which of the following best explains why nitrosoureas require a longer interval between cycles than most other alkylating agents?

  • ALomustine undergoes enterohepatic recirculation that extends its effective half-life to 6 weeks, requiring this interval to achieve complete drug elimination before re-dosing
  • BNitrosoureas produce myelosuppression with a nadir at 4 to 6 weeks rather than the 10 to 14 days seen with most cytotoxic drugs; administering a second cycle before the nadir resolves risks overlapping suppressions that can cause aplasia
  • CThe blood-brain barrier retains lomustine in the central nervous system for 6 weeks, and re-dosing before clearance risks central nervous system toxicity from drug accumulation
  • DNitrosoureas require 6 weeks for complete deoxyribonucleic acid repair of interstrand cross-links; earlier re-dosing interferes with repair and paradoxically reduces efficacy

Correct Answer

B — Nitrosoureas produce myelosuppression with a nadir at 4 to 6 weeks rather than the 10 to 14 days seen with most cytotoxic drugs; administering a second cycle before the nadir resolves risks overlapping suppressions that can cause aplasia

Rationale

The defining pharmacotoxicological feature of nitrosoureas is delayed and prolonged myelosuppression. Unlike most cytotoxic agents whose myelosuppressive nadir occurs 10 to 14 days after administration, nitrosoureas produce a nadir at 4 to 6 weeks, with full marrow recovery requiring 6 to 8 weeks. The mechanism is not fully characterized but relates to the alkylation of slowly dividing hematopoietic progenitors. Administering a subsequent cycle on a standard 3-week schedule would deliver the second dose before the first cycle's nadir has occurred, producing cumulative overlapping suppressions that can cause life-threatening aplasia. The 6-week minimum interval is determined by this toxicity kinetic, not by drug elimination half-life, central nervous system retention, or deoxyribonucleic acid repair timelines.

Question 12

A patient with glioblastoma is found to have an unmethylated O6-methylguanine-deoxyribonucleic acid methyltransferase promoter. Which of the following best explains why this finding predicts reduced benefit from temozolomide?

  • AAn unmethylated promoter increases temozolomide efflux through P-glycoprotein, reducing intracellular drug concentrations below cytotoxic thresholds
  • BAn unmethylated promoter causes overexpression of mismatch repair proteins that rapidly correct O6-guanine lesions before they can trigger apoptosis
  • CAn unmethylated promoter reduces the spontaneous hydrolysis rate of temozolomide, decreasing the amount of methylating species generated in tumor tissue
  • DAn unmethylated promoter allows robust O6-methylguanine-deoxyribonucleic acid methyltransferase expression; the enzyme directly reverses O6-guanine alkylation in a stoichiometric repair reaction, removing the lesions that would otherwise cause cell death

Correct Answer

D — An unmethylated promoter allows robust O6-methylguanine-deoxyribonucleic acid methyltransferase expression; the enzyme directly reverses O6-guanine alkylation in a stoichiometric repair reaction, removing the lesions that would otherwise cause cell death

Rationale

Temozolomide kills tumor cells by methylating deoxyribonucleic acid at the O6 position of guanine, producing lesions that trigger futile mismatch repair cycles and ultimately cause double-strand breaks and apoptosis. O6-methylguanine-deoxyribonucleic acid methyltransferase is a repair enzyme that directly and stoichiometrically reverses O6-guanine alkylation, consuming one enzyme molecule per repair event. When the O6-methylguanine-deoxyribonucleic acid methyltransferase gene promoter is unmethylated, the gene is expressed at normal or high levels, the protein is abundant, and O6-guanine lesions are efficiently repaired before they can cause lethal deoxyribonucleic acid damage. Promoter methylation silences the gene, eliminates this repair capacity, and sensitizes the tumor. The mechanism is direct enzymatic reversal of the drug's primary cytotoxic lesion — not efflux, not mismatch repair, and not a change in drug activation rate.

Question 13

A patient receiving ifosfamide develops confusion, visual hallucinations, and ataxia beginning 18 hours after the start of infusion. The treating team suspects ifosfamide encephalopathy. Which of the following is the most appropriate treatment?

  • AMethylene blue intravenously — it corrects the mitochondrial dysfunction caused by the neurotoxic ifosfamide metabolite chloroacetaldehyde
  • BN-acetylcysteine intravenously — it replenishes glutathione depleted by chloroacetaldehyde and restores neuronal antioxidant capacity
  • CFlumazenil intravenously — it reverses chloroacetaldehyde-mediated gamma-aminobutyric acid receptor potentiation and restores normal consciousness
  • DSodium thiosulfate intravenously with sodium bicarbonate — conjugates chloroacetaldehyde in the cerebrospinal fluid through a thiol exchange reaction

Correct Answer

A — Methylene blue intravenously — it corrects the mitochondrial dysfunction caused by the neurotoxic ifosfamide metabolite chloroacetaldehyde

Rationale

Ifosfamide encephalopathy is caused by chloroacetaldehyde, a neurotoxic metabolite generated during ifosfamide side-chain oxidation. Chloroacetaldehyde disrupts mitochondrial function in neurons, impairing cellular energy production. Methylene blue is given intravenously to correct this mitochondrial dysfunction — it acts as an electron carrier that bypasses the block and restores energy metabolism in affected neurons. It is administered at 50 mg every 4 to 8 hours until symptoms resolve, and is also used prophylactically in subsequent cycles when encephalopathy has previously occurred. N-acetylcysteine is used for ifosfamide-induced hemorrhagic cystitis prevention as a mucosal thiol donor, not for encephalopathy. Flumazenil reverses benzodiazepine sedation and does not address chloroacetaldehyde toxicity. Sodium thiosulfate and bicarbonate are used for cisplatin nephrotoxicity rescue and cyanide poisoning, not for ifosfamide encephalopathy.

Question 14

Oxaliplatin retains antitumor activity in colorectal cancers that have deficient mismatch repair, whereas cisplatin does not. Which of the following best explains this difference?

  • AOxaliplatin is actively transported into mismatch repair-deficient cells by a transporter that is upregulated when mismatch repair proteins are absent
  • BMismatch repair-deficient cells have elevated glutathione levels that preferentially inactivate cisplatin but not oxaliplatin
  • COxaliplatin produces structurally distinct platinum-strand adducts that are not recognized by mismatch repair proteins, allowing cytotoxicity to proceed independently of mismatch repair status
  • DCisplatin requires mismatch repair activity to generate the strand breaks that trigger apoptosis; without mismatch repair, cisplatin-induced lesions are not converted into a lethal signal

Correct Answer

C — Oxaliplatin produces structurally distinct platinum-strand adducts that are not recognized by mismatch repair proteins, allowing cytotoxicity to proceed independently of mismatch repair status

Rationale

Cisplatin and carboplatin form platinum-strand adducts that are recognized by mismatch repair proteins. In cells with intact mismatch repair, the proteins bind these adducts and ultimately signal apoptosis; in mismatch repair-deficient cells, the adducts are not recognized and the apoptotic signal is not generated, producing resistance. Oxaliplatin forms structurally distinct platinum-strand adducts that the mismatch repair machinery does not recognize, so its cytotoxicity does not depend on mismatch repair recognition — oxaliplatin kills both mismatch repair-proficient and mismatch repair-deficient cells. This difference explains the clinical utility of oxaliplatin in colorectal cancer, a tumor type with frequent mismatch repair deficiency. Differential transporter expression, glutathione inactivation selectivity, and active transport upregulation do not account for this distinction.

Clinical Correlations  ·  Questions 15–18

Apply pharmacological knowledge to clinical scenarios. Each vignette presents a patient situation; the question tests mechanism of action or drug selection.

Question 15

A 38-year-old woman with soft tissue sarcoma receives cyclophosphamide with mesna and standard intravenous hydration. Due to a nursing error, her hydration was reduced to one-third of the prescribed volume. She subsequently develops gross hematuria. Which of the following best explains why inadequate hydration contributed to her bladder injury despite mesna administration?

  • AReduced hydration increased plasma acrolein concentration, overwhelming mesna's capacity to conjugate the toxin before it reached the bladder
  • BMesna must reach the bladder lumen at sufficient concentration to conjugate acrolein; inadequate hydration reduced urinary mesna concentration below the level needed to protect the bladder epithelium
  • CDehydration impaired renal mesna clearance, causing mesna to accumulate in the bloodstream and be inactivated by oxidation before reaching the urine
  • DReduced hydration concentrated acrolein in the bladder wall rather than the lumen, placing the toxin beyond the reach of mesna regardless of urinary concentration

Correct Answer

B — Mesna must reach the bladder lumen at sufficient concentration to conjugate acrolein; inadequate hydration reduced urinary mesna concentration below the level needed to protect the bladder epithelium

Rationale

Mesna protects the bladder by conjugating acrolein in the urine before it can contact and damage the urothelium. For this mechanism to work, mesna must be present in the bladder lumen at a high enough concentration to neutralize the acrolein being excreted. Adequate hydration serves two purposes: it dilutes acrolein in the urine, reducing its contact concentration with the bladder wall, and it maintains urinary flow that delivers mesna to the bladder in sufficient volume. When hydration is severely reduced, urine production falls and the mesna reaching the bladder is insufficient to conjugate all the acrolein present, allowing bladder injury to occur. This is why vigorous hydration is an essential component of the protective regimen alongside mesna — mesna alone at reduced urinary volume is not reliably protective. Plasma acrolein concentration is not the critical variable, dehydration does not cause mesna accumulation and inactivation in blood, and acrolein does not concentrate preferentially in the bladder wall.

Question 16

A 54-year-old man with anaplastic oligodendroglioma completed his first cycle of lomustine six weeks ago and is scheduled to begin his second cycle. His complete blood count shows a platelet count of 48,000 per microliter and an absolute neutrophil count of 800 per microliter. His oncologist delays the second cycle. At a follow-up three weeks later — nine weeks after the first cycle — his counts have recovered and treatment resumes. Which of the following best explains why his nadir occurred so much later than expected for most cytotoxic agents?

  • ALomustine undergoes delayed hepatic activation, producing the active alkylating species only after several weeks of metabolism
  • BLomustine is lipophilic and accumulates in fat tissue, releasing slowly into the circulation over weeks and causing prolonged bone marrow exposure
  • CLomustine selectively targets late progenitor cells rather than stem cells, and late progenitors take longer to deplete because they have a slower cell cycle
  • DNitrosoureas produce delayed myelosuppression with a nadir at 4 to 6 weeks after dosing, substantially later than the 10 to 14 day nadir seen with most other cytotoxic agents, because they damage early hematopoietic progenitors that take weeks to deplete the mature cell pool

Correct Answer

D — Nitrosoureas produce delayed myelosuppression with a nadir at 4 to 6 weeks after dosing, substantially later than the 10 to 14 day nadir seen with most other cytotoxic agents, because they damage early hematopoietic progenitors that take weeks to deplete the mature cell pool

Rationale

The timing of myelosuppression after chemotherapy depends on which level of the hematopoietic hierarchy is affected. Most cytotoxic agents damage actively dividing precursors in the mid-to-late progenitor compartment; because these cells are days to a week from maturity, the blood count nadir appears at 10 to 14 days. Nitrosoureas — including lomustine and carmustine — are unusual in that they damage early hematopoietic progenitors and possibly hematopoietic stem cells. Because early progenitors must progress through multiple cell divisions before generating mature blood cells, the depletion of circulating cells takes considerably longer to manifest, producing a nadir at 4 to 6 weeks. This delayed nadir is the pharmacological rationale for the minimum 6-week interval between nitrosourea cycles — a shorter interval risks dosing during active marrow suppression from the previous cycle. Delayed hepatic activation, fat tissue accumulation and slow release, and selective late progenitor targeting do not explain the characteristic delayed nadir of this drug class.

Question 17

A 67-year-old woman with metastatic colorectal cancer undergoes molecular profiling of her tumor. Results show microsatellite instability-high status due to loss of mismatch repair protein expression. Her oncologist recommends an oxaliplatin-based regimen rather than a cisplatin-based regimen for the platinum component of her treatment. Which of the following best explains this preference?

  • AOxaliplatin forms platinum-strand adducts that are not recognized by mismatch repair proteins, so its cytotoxicity is preserved in microsatellite instability-high tumors where cisplatin loses activity
  • BOxaliplatin is preferentially approved for colorectal cancer because it has lower nephrotoxicity than cisplatin, making it safer for elderly patients with reduced renal reserve
  • CCisplatin is contraindicated in colorectal cancer because it causes severe mucositis when combined with fluorouracil, whereas oxaliplatin does not share this interaction
  • DMicrosatellite instability-high tumors overexpress a transporter that effluxes cisplatin but not oxaliplatin, producing pharmacokinetic resistance to cisplatin specifically

Correct Answer

A — Oxaliplatin forms platinum-strand adducts that are not recognized by mismatch repair proteins, so its cytotoxicity is preserved in microsatellite instability-high tumors where cisplatin loses activity

Rationale

Mismatch repair proteins recognize the platinum-strand adducts formed by cisplatin and carboplatin as part of the signaling process that ultimately triggers apoptosis. When mismatch repair is absent — as in microsatellite instability-high tumors — cisplatin adducts are not recognized, the apoptotic signal is not generated, and the tumor is resistant. Oxaliplatin forms structurally distinct adducts that the mismatch repair machinery does not recognize, which means cytotoxicity is generated through a mismatch repair-independent pathway and is preserved regardless of mismatch repair status. This mechanistic distinction is the pharmacological basis for preferring oxaliplatin in mismatch repair-deficient colorectal cancer. Nephrotoxicity differences, mucositis interactions, and differential transporter efflux are not the explanation for this clinical preference in microsatellite instability-high disease.

Question 18

A 28-year-old man with metastatic testicular germ cell tumor achieves a complete response after three cycles of BEP (bleomycin, etoposide, cisplatin). His oncologist is asked whether carboplatin could substitute for cisplatin in future cycles to reduce nephrotoxicity and ototoxicity. Which of the following best explains why carboplatin cannot replace cisplatin in this curative-intent regimen?

  • ACarboplatin is not absorbed into testicular tissue, limiting its cytotoxic effect against germ cell tumor metastases
  • BCarboplatin has a shorter half-life than cisplatin and cannot maintain the sustained platinum-deoxyribonucleic acid adduct exposure required for germ cell tumor cytotoxicity
  • CCisplatin and carboplatin form identical platinum-deoxyribonucleic acid adducts, so resistance mechanisms confer complete cross-resistance; additionally, the curative outcomes in germ cell tumors are established specifically for cisplatin-containing regimens and have not been replicated with carboplatin substitution
  • DCarboplatin is a prodrug that requires hepatic activation to form the active platinum species, and reduced hepatic function in patients who have received prior chemotherapy impairs its conversion

Correct Answer

C — Cisplatin and carboplatin form identical platinum-deoxyribonucleic acid adducts, so resistance mechanisms confer complete cross-resistance; additionally, the curative outcomes in germ cell tumors are established specifically for cisplatin-containing regimens and have not been replicated with carboplatin substitution

Rationale

Cisplatin and carboplatin both form N7-guanine platinum-deoxyribonucleic acid adducts — the adducts are chemically identical, differing only in their carrier ligand. Because the cytotoxic lesions are the same, resistance mechanisms that arise against one agent confer complete cross-resistance to the other. Beyond cross-resistance, the landmark cure rates for metastatic testicular germ cell tumors exceeding 80% even in disseminated disease were established with BEP using cisplatin; prospective data demonstrating equivalent curative outcomes with carboplatin substitution do not exist. In curative-intent settings, substitution based on toxicity preference rather than equivalent efficacy data is not acceptable. Carboplatin is not limited by tissue distribution, does not have a shorter half-life than cisplatin in the relevant pharmacokinetic sense, and is not a prodrug requiring hepatic activation.